For the given reactions Sn 2 + + 2 e - → Sn Sn 4 + + 4 e - → Sn the electrode potentials are ; E Sn 2 + / Sn ° = - 0 . 140   V and E Sn 4 + / Sn ° = 0 . 010   V . The magnitude of standard electrode potential for Sn 4 + / Sn 2 + i.e. E Sn 4 + / Sn 2 + ° is____ × 10 - 2   V (Nearest integer)

Step-by-step solution

(i) Sn 2 + + 2 e - ⟶ Sn                   E 1 0 = - 0 . 14   V ΔG 1 0 = - 2   F - 0 . 14 (ii) Sn 4 + + 4 e - ⟶ Sn               E 2 0 = + 0 . 010   V ΔG 2 0 = - 4 F + 0 . 010 Target Sn 4 + + 2 e - ⟶ Sn 2 +             E 3 0 = ? ΔG 3 0 = - 2   F E 3 0 Target Eq. = Eq. ii - Eq. i - 2 F E 3 0 = - 4 F 0 . 010 - - 2 F - 0 . 14 E 3 0 = 4 × 0 . 010 + 2 &