JEE Main2017ChemistryElectrochemistryActual
Given E Cl 2 / Cl - o = 1 .36 V , E Cr 3 + / Cr o = - 0 .74 V E Cr 2 O 7 2 - / Cr 3 + o = 1 .33 V , E MnO 4 - / Mn 2 + o = 1 .51 V . Among the following, the strongest reducing agent is:
Options
- AMn 2 +
- BCr 3 +
- CCl -
- DCr
Correct answer
D. Cr
Step-by-step solution
Strongest reducing agent has the highest tendency to get oxidised. Higher the oxidation potential, higher is the tendency to get oxidised. Reduction potential of Cr 3 + is least ( E Cr 3 + / Cr o =   - 0 .74 V ) which indicates that oxidation potential of Cr is highest ( E Cr / Cr 3 + o =   0 .74 V ). Thus, Cr is strongest reducing agent.