JEE Main202623 January 2026Evening ShiftChemistryGeneral Organic ChemistryActual
In Carius method 0.2425 g of an organic compound gave 0.5253 g silver chloride. The percentage of chlorine in the organic compound is
Options
- A34.79 %
- B37.57 %
- C87.65 %
- D53.58 %
Correct answer
D. 53.58 %
Step-by-step solution
In Carius method, chlorine is converted to AgCl. Molar mass of AgCl = 143.5 g/mol. Moles of AgCl formed = 0.5253 / 143.5 = 0.003661 mol. Since each AgCl contains one Cl atom, moles of Cl = 0.003661 mol. Mass of Cl = 0.003661 × 35.5 = 0.1300 g. Percentage of Cl = (0.1300 / 0.2425) × 100 = 53.58%.