Given below are two statements: Statement I : (CH_ 3 )_ 3 C is more...

Statement I: In the tert-butyl carbocation $(CH_3)_3C^+$, there are three methyl groups attached to the carbocationic carbon. Each methyl group has 3 $\alpha$-hydrogens, making a total of 9 $\alpha$-hydrogens. Thus, 9 hyperconjugation interactions are possible, which significantly stabilize the carbocation. Statement I is true.
Statement II: In the methyl carbocation $CH_3^+$, there are no $\alpha$-carbons and consequently no $\alpha$-hydrogens. Hyperconjugation requires the presence of at least one $\alpha$-hydrogen on a carbon adjacent to the $sp^2$ hybridized carbocation center. Therefore, zero hyperconjugation interactions are possible in $CH_3^+$. Statement II is false because it claims three hyperconjugation interactions are possible.
Conclusion: Statement I is true but Statement II is false.