Following Kjeldahl's method, 1 g of organic compound released ammonia, that neutralised 10 mL of 2 MH 2 SO 4 . The percentage of nitrogen in the compound is _______ % .

Step-by-step solution

H 2 SO 4 + 2 NH 3 → NH 4 2 SO 4 Equivalent of NH 3 = Equivalent of H 2 SO 4 moles of NH 3 n NH 3 × 1 = 2 × 10 × 2 1000 = 4 × 10 - 2 moles Moles of nitrogen = 4 × 10 - 2 moles Weight of Nitrogen = 4 × 10 - 2 × 14 = 56 × 10 - 2 gm Percent of nitrogen = 56 × 10 - 2 weight of the compound × 100 = 56 × 10 - 2 1 × 100 = 56 %