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Optically active was found to have lost its optical activity after standing in water containing a few drops of acids, mainly due to the formation of

Options

  1. ACH ₃- CH ₂- CH = CH ₂
  2. BCH ₃- CH = CH - CH ₃
  3. CCH ₃- CH ₂- CH ₂- CH ₂- OH

Correct answer

B. CH ₃- CH = CH - CH ₃

Step-by-step solution

The above optically active compound undergo dehydration with few drops of acid and form stable alkene through the formation of stable carbocation.

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