Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
99 Percentile Qs Bank for JEE MainChemistryChemical Kinetics

Consider the following gaseous decomposition of ozone: 2 O 3 g ⟶ 3 O 2 g . The observed rate law is r = - d O 3 dt = k O 3 2 O 2 If the above reaction occurs through the following mechanism: O 3 ⇌ K O 2 + O fast equilibrium O + O 3 ⟶ k 1 2 O 2 slow Then, which of the following relation is correct?

Options

  1. Ak = k 1
  2. Bk = Kk 1
  3. Ck = K
  4. DNone of these

Correct answer

B. k = Kk 1

Step-by-step solution

In Complex Reaction Rate law is defined by the slowest step. So According to slowest step Rate Law Expression can be represented as: Rate law = r = k 1 O O 3 ...........(1) Now Intermediate term ie [O] can never comes in Rate Law Expression.So to eliminate it,we apply Equilibrium constant Expression on Reversible Equation. K = O 2 O O 3 . . . . . . . . . . . . . ( 2 )         ( K = Equilibrium   constant ) O = K O 3 O 2 On Puting value of [O] in Equation 1 , we get ⇒   

Practice Chemical Kinetics on Quantrex Academy →

More from Chemical Kinetics

For a reversible reaction R P , at constant temperature, both the forward and the backward reactions are first order elementary reactions with rate constants k_f and k_b , respecti 2026For a first-order reaction R P at a given temperature, k is the rate constant. For this reaction, at the given temperature, the concentrations of R and P at a time t are [ R ] and 2026Given below are two statements: R=8.314 J K ⁻¹ mol ⁻¹ and 1 cal =4.2 J Statement I: When E_a=12.6 kcal/mol, the room temperature rate constant is doubled by a 10 ,^ C increase in t 2026Decomposition of a hydrocarbon follows the equation k = (5.5 10¹¹ , s ⁻¹) ,e^ -28000 , K T . The activation energy of reaction is __________ kJ mol ⁻¹ . (Nearest Integer) Given : R 2026For a reaction A P at T K , the half life (t_ 1/2 ) is plotted as a function of initial concentration [A]₀ of A as given below. The value of x in the given figure is _______ s (Nea 2026First order gas phase reaction A B + C p_i = initial pressure of gas A, p_t = total pressure of the reaction mixture at time t Expression of rate constant ( k ) is 2026If the half life of a first order reaction is 6.93 minutes then the time required for completion of 99 % of the reaction will be _____ minutes. (Given : 2 = 0.3010 ) 2026Consider the given graph showing variation of reactant concentration with time. Three different reactions were started with identical initial concentration of reactants. Which of t 2026 Full Chemical Kinetics list All 99 Percentile Qs Bank for JEE Main PYQs