A particular reaction has a rate constant 1.15 10⁻³ ~s ⁻¹ . How long does it take for 6 ~g of the reactant of reduce to 3 ~g ? ( 2=0.301)

Step-by-step solution

Given, rate constant (k)=1.15 10⁻³ ~s ⁻¹ Reaction time = ? Initial amount of reactant (A_o )=6 ~g Final amount of reactant (A_f )=3 ~g From rate constant equation, aligned k & = 2.303 t A_o A_f 1.15 10⁻³ & = 2.303 t 6 3 t & = 2.303 1.15 10⁻³ 6 3 = 2.303 1.15 10⁻³ .3010 t & =.6027 10⁺³ ~s or t & =603 ~s aligned