99 Percentile Qs Bank for JEE MainChemistryChemical Kinetics
The rate equation for a first-order reaction is given by R = R 0 e - kt . A straight line with positive slope is obtained by plotting ( R 0 = Initial concentration of the reactant, R = concentration of the reactant at time t )
Options
- Alog R 0 R Vs time
- BR Vs time
- Clog R Vs time
- Dlog R R 0 Vs time
Correct answer
A. log R 0 R Vs time
Step-by-step solution
First-order reaction is the rate of reaction is proportional to the first power of the concentration of the reactant R . R → P Rate = - d R dt = kR Rate equation, R = R 0 e - kt Comparing with y = mx + c , if we plot lnR against t , we get a straight line with a slope = - k and intercept = ln R 0 . Also, k = 2 . 303 t log R 0 R ⇒ log R 0 R = kt 2 . 303 If we plot a graph between log R 0 R Vs t , slope = k 2 . 303 .