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JEE Main
Exam
JEE Main
Subject
Chemistry
Chapter
p Block Elements (Group 13 & 14)

JEE Main · Chemistry · p Block Elements (Group 13 & 14)

Ge (II) compounds are powerful reducing agents whereas Pb (IV)...

GeGe (II) compounds are powerful reducing agents whereas PbPb (IV) compounds are strong oxidants. It is due to -

Options

  1. APbPb is more electropositive than GeGe
  2. BIonization potential of Lead is less than that of GeGe
  3. CIonic radii of Pb2+{Pb}^{2 +} and Pb4+{Pb}^{4 +} are larger than those of Ge2+{Ge}^{2 +} and Ge4+{Ge}^{4 +}
  4. DMore pronounced inert pair effect in lead than in GeGe

Correct answer

D. More pronounced inert pair effect in lead than in GeGe

Step-by-step solution

Due to inert pair effect, the +2+ 2 oxidation state stability increases down the14th{14}^{th} group, and +4+ 4 oxidation state stability decreases down the group. Ge(II)Ge ( II ) tends to acquire Ge(IV)Ge ( IV ) state by loss of electrons. Hence,~it~acts as a~reducing agent.& Pb(IV)Pb ( IV ) tends to acquire Pb(II)Pb ( II )& oxidation state& by gain of electrons. Hence, it acts as an& oxidising agent.

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