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JEE Main
Exam
JEE Main
Subject
Chemistry
Chapter
p Block Elements (Group 13 & 14)

JEE Main · Chemistry · p Block Elements (Group 13 & 14)

An element 'E' gives following reaction sequence : E + N _ 2...

An element 'E' gives following reaction sequence :

E+N2→Hightemp.EN→Hightemp.waterE(OH)3+NH3E + {N}_{2}\overset{Hightemp .}{→}EN\mathop{→}_{Hightemp .}^{water}E ( OH{)}_{3} + {NH}_{3}

Element E may be:

Options

  1. ABB or AlAl
  2. BAny element of B family
  3. Cin or TiTi
  4. Donly AlAl

Correct answer

A. BB or AlAl

Step-by-step solution

Aluminium and boron forms nitride with nitrogen at higher temperature due to the high bond energy of nitrogen.

The reaction of boron and nitrogen forms boron nitride which is then hydrolysed to form products as follows:

2B+N2→Hightemp.2BN→Hightemp.waterB(OH)3+NH32B + {N}_{2}\overset{Hightemp .}{→}2BN\mathop{→}_{Hightemp .}^{water}B ( OH{)}_{3} + {NH}_{3}

Aluminium forms aluminium nitride and it further hydrolysed as follows:

2Al+N2→Hightemp.2AlN→Hightemp.waterAl(OH)3+NH32Al + {N}_{2}\overset{Hightemp .}{→}2AlN\mathop{→}_{Hightemp .}^{water}Al ( OH{)}_{3} + {NH}_{3}

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