99 Percentile Qs Bank for JEE MainChemistryPractical Chemistry
X → KOH Y (gas turns red litmus blue) + Z → Zn + KOH Y (gas) . X → Δ gas (does not support combustion) Identify (X) to (Z):
Options
- AX = NH 4 NO 2 Y = NH 3 Z = KNO 2
- B X = ( NH 4 ) 2 Cr 2 O 7 Y = NH 3 Z = Cr 2 O 3
- CX = ( NH 4 ) 2 SO 4 Y = NH 3 Z = K 2 SO 4
- DX = NH 4 NO 3 Y = NH 3 Z = KNO 3
Correct answer
A. X = NH 4 NO 2 Y = NH 3 Z = KNO 2
Step-by-step solution
NH 4 NO 2 X + KOH → NH 3 ↑ Y + KNO 2 Z + H 2 O NO 2 - Z + 3 Zn + 5 OH - + 5 H 2 O → 3 Zn OH 4 2 - soluble + NH 3 ↑ Y NH 4 NO 2 → Δ N 2 ↑ + 2 H 2 O X (Does not support combustion)