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The mass of AgCl precipitated when a solution containing 11 . 70   g of NaCl is added to a solution containing 3 . 4   g of AgNO 3 is [Atomic mass of Ag = 108 , Atomic mass of Na = 23 ]

Options

  1. A2 . 87   g
  2. B6 . 8   g
  3. C5 . 74   g
  4. D1 . 17   g

Correct answer

A. 2 . 87   g

Step-by-step solution

NaCl + AgNO 3 → NaNO 3 + AgCl 58 . 5   g 170 143 . 5   g (Limiting reagent) NaCl : AgNO 3 Required ratio 58 . 5 : 170 Given ratio 11 . 70 : 3 . 4 (Limiting reagent) 170   g   AgNO 3 → 143 . 5   g   AgCl ∴   3 . 4   g   AgNO 3 → x x = 3 . 4 × 143 . 5 170 = 2 . 879   g

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