25.4   g m of iodine and 7.1   g m chlorine are made to react to give a mixture of I C l and I C l 3 .The number of moles of I C l and I C l 3 formed are respectively

Step-by-step solution

I 2 + 2 C l 2 ⟶   I C l + I C l 3 Moles of I 2 r e a c t e d = wt . given molecular   weight = 25.4 254 = 0.1   m o l Moles of C l 2 reacted = 7.1 71 = 0.1   m o l . Chlorine is the limiting reagent. Hence no. of moles of I C l   p r o d u c e d = n o . of moles of I C l 3   p r o d u c e d = no :   of   moles   of   products no :   of   moles   of   limiting   reagent = 0.1 2 = 0.05   m o l e s .