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99 Percentile Qs Bank for JEE MainChemistrySome Basic Concepts of Chemistry

In a certain operation, 358   g of TiCl 4 reacts with 96   g of Mg . Calculate the yield of Ti if 32   g of Ti is actually obtained [atomic weight of Ti = 48 , atomic weight of Mg = 24 ]

Options

  1. A35 . 46 %
  2. B  66 . 6 %
  3. C100 %
  4. D60 %

Correct answer

A. 35 . 46 %

Step-by-step solution

Balanced equation : TiCl 4 + 2 Mg → Ti + 2 MgCl 2 Initial moles of TiCl 4 = mass molar   mass = 358 190 = 1 . 88 Initial moles of Mg = 96 24 = 4 For finding limiting reagent, moles of both the reactants are divided by their coefficients and the least value gives L.R. For TiCl 4 , 1 . 88 1 = 1 . 88 For Mg = 4 2 = 2 ∴ TiCl 4 is the limiting reagent So, on the basis of L.R., product amount will be calculated. ∵ One mole of TiCl 4 produces one mole of Ti . Number of moles of Ti produced by 1 . 88

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