4 mol of a mixture of Mohr's salt and F e 2 S O 4 3 requires 500 ml of 1 M, K 2 C r 2 O 7 for complete oxidation in acidic medium. The mole % of the Mohr's salt in the mixture is

Step-by-step solution

C r 2 O 7 2 - + 6 F e 2 + ( n = 1 ) (Mohr's salt) + 14 H + → 2 C r 3 + + 6 F e 3 + + 7 H 2 O Equivalent of F e 2 + = moles of Mohr's salt = equivalent of K 2 C r 2 O 7 = 500 × 1 0 - 3 × 6 × 1 = 3 Hence mole percent of Mohr's salt = 3 4 × 100 = 75