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The number of molecules of CO ₂ liberated by the complete combustion of 0.1 ~g atom of graphite in air is

Options

  1. A3.01 10²²
  2. B6.02 10²³
  3. C6.02 10²²
  4. D3.01 10²³

Correct answer

C. 6.02 10²²

Step-by-step solution

1 ~mol C (s) + O ₂(g) 1 ~mol CO ₂(g) =6.023 10²³ 1 mole of graphite on complete combustion gives CO ₂=6.023 10²³ molecules 0.1 mole of graphite will give CO ₂= 6.023 10²³ 0.1 1 =6.023 10²²

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