NX is produced by the following step of reactions M + X 2 → MX 2 3 MX 2 + X 2 → M 3 X 8 M 3 X 8 + N 2 CO 3 → NX + CO 2 + M 3 O 4 How much M (metal) is consumed to produce 206   gm of NX . ( Take atomic weight of M = 56 ,   N = 23 ,   X = 80 )

Step-by-step solution

The sequence of reactions are as follows: M + X 2 → MX 2 MX 2 + X 2 → M 3 X 8 M 3 X 8 + Na 2 CO 3 → NX + CO 2 + M 3 O 4 moles of NX = mass   of   NX molar   mass   of   NX = 206 103 = 2   mol POAC (Principle of atom conservation) for X Atom : Number of X atom in M 3 X 8 = Number of X Atom in NX 8 [Number of mole M 3 X 8 ] = 1 [ of Number of mole of NX ] Number of moles of M 3 X 8    = 2 8 = 1 4 mole Now, POAC for M Atom: 3 [Number of mole of M 3 X 8 ] = 1 &#