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The chloride of a metal contains 71% chlorine by weight and the vapour density of it is 50. The atomic weigh of the metal will be:

Options

  1. A29
  2. B58
  3. C35.5
  4. D71

Correct answer

A. 29

Step-by-step solution

Mol. wt. of metal chloride = 50 × 2 = 100 Let metal chloride be metal chlorine then Equivalent of metal = Equivalents of chlorine = W m E m = W Cl E Cl or 29 E = 71 35 .5 E = 29 2 Now a + 35.5 n = 100 or n × E + 35 × 5n = 100 ∴ n = 2 Therefore, a = 2 × E = 2 × 29 2 = 29

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