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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Introduction to Physics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Introduction to Physics

Determine the dimensions of angular speed ω . Some of the equations...

Determine the dimensions of angular speed ω\omega.
Some of the equations involving related quantities are
ω=θ2−θ1t2−t1\omega = \dfrac{\theta_2 - \theta_1}{t_2 - t_1}, α=ω2−ω1t2−t1\alpha = \dfrac{\omega_2 - \omega_1}{t_2 - t_1}, Γ=F⋅r\Gamma = F \cdot r and I=mr2I = mr^2.
The symbols have standard meanings.

Options

  1. ALT−1L T^{-1}
  2. BMLT−1M L T^{-1}
  3. CT−1T^{-1}
  4. DT−2T^{-2}

Correct answer

C. T−1T^{-1}

Step-by-step solution

Angular speed ω\omega is given by the relation ω=θ2−θ1t2−t1\omega = \dfrac{\theta_2 - \theta_1}{t_2 - t_1}.

Angular displacement θ\theta is the ratio of arc length to radius, making it a dimensionless quantity. Its dimensional formula is M0L0T0M^0 L^0 T^0.

Time tt has the dimensional formula TT.

Substituting the dimensions into the equation for angular speed:

[ω]=M0L0T0T=T−1[\omega] = \dfrac{M^0 L^0 T^0}{T} = T^{-1}
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