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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Introduction to Physics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Introduction to Physics

Determine the dimensions of torque . Some of the equations...

Determine the dimensions of torque Γ\Gamma.
Some of the equations involving related quantities are
ω=θ2−θ1t2−t1\omega = \dfrac{\theta_2 - \theta_1}{t_2 - t_1}, α=ω2−ω1t2−t1\alpha = \dfrac{\omega_2 - \omega_1}{t_2 - t_1}, Γ=F⋅r\Gamma = F \cdot r and I=mr2I = mr^2.
The symbols have standard meanings.

Options

  1. AMLT−2ML T^{-2}
  2. BML2T−2ML^2 T^{-2}
  3. CML2T−1ML^2 T^{-1}
  4. DML2ML^2

Correct answer

B. ML2T−2ML^2 T^{-2}

Step-by-step solution

Torque Γ\Gamma is given by the product of force FF and distance rr.

Γ=F⋅r\Gamma = F \cdot r

The dimensional formula of force FF is [MLT−2][M L T^{-2}].

The dimensional formula of distance rr is [L][L].

Substituting these dimensions into the formula for torque:

[Γ]=[MLT−2]×[L]=[ML2T−2][\Gamma] = [M L T^{-2}] \times [L] = [M L^2 T^{-2}]
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