Determine the dimensions of the electric field E . The relevant equations are F = qE , F = qvB , and B = (μ_0 I)/(2 π a) ; where F is force, q is charge, v is speed, I is current, and a is distance.

Correct answer: C. MLT^ -3 I^ -1 From the relation F = qE , the electric field E is given by E = (F)/(q) . The dimensional formula for force F is MLT^ -2 . The dimensional formula for charge q is IT . Substituting these dimensions, we get: [E] = MLT^ -2 IT = MLT^ -3 I^ -1

Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Introduction to Physics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Introduction to Physics

Determine the dimensions of the electric field E . The relevant...

Determine the dimensions of the electric field

E

. The relevant equations are

F = qE

F = qvB

, and

B = \dfrac{\mu_0 I}{2 \pi a}

; where

F

is force,

q

is charge,

v

is speed,

I

is current, and

a

is distance.

Options

A $MLT^{-2} I^{-1}$
B $MT^{-3} I^{-1}$
C $MLT^{-3} I^{-1}$
D $ML^2T^{-3} I^{-1}$

Correct answer

C. $MLT^{-3} I^{-1}$

Step-by-step solution

From the relation

F = qE

, the electric field

E

is given by

E = \dfrac{F}{q}

.

The dimensional formula for force

F

MLT^{-2}

.

The dimensional formula for charge

q

IT

.

Substituting these dimensions, we get:

[E] = \dfrac{MLT^{-2}}{IT} = MLT^{-3}I^{-1}

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