Determine the dimensions of moment of inertia $I$ .
Some of the equations involving related quantities are
$\omega = \dfrac{\theta_2 - \theta_1}{t_2 - t_1}$ , $\alpha = \dfrac{\omega_2 - \omega_1}{t_2 - t_1}$ , $\Gamma = F \cdot r$ and $I = mr^2$ .
The symbols have standard meanings.

Question

Determine the dimensions of moment of inertia

I

.
Some of the equations involving related quantities are

\omega = \dfrac{\theta_2 - \theta_1}{t_2 - t_1}

,

\alpha = \dfrac{\omega_2 - \omega_1}{t_2 - t_1}

,

\Gamma = F \cdot r

and

I = mr^2

.
The symbols have standard meanings.

Quantrex Academy · Accepted Answer

Correct answer: B. ML^2

From the given equation, I = mr^2 . The dimensional formula for mass m is [M] . The dimensional formula for distance r is [L] . Substituting these dimensions, the dimensional formula for moment of inertia I is [M][L]^2 = [ML^2] .

Determine the dimensions of moment of inertia I . Some of the...

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