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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Introduction to Physics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Introduction to Physics

Find the dimensions of the gas constant R . An equation involving...

Find the dimensions of the gas constant RR. An equation involving this quantity is PV=nRTPV = nRT.

Options

  1. AMLT−2K−1(mol)−1M L T^{-2} K^{-1} (\text{mol})^{-1}
  2. BML2T−2K−1(mol)−1ML^2 T^{-2} K^{-1} (\text{mol})^{-1}
  3. CML2T−1K−1(mol)−1ML^2 T^{-1} K^{-1} (\text{mol})^{-1}
  4. DML2T−2K−1ML^2 T^{-2} K^{-1}

Correct answer

B. ML2T−2K−1(mol)−1ML^2 T^{-2} K^{-1} (\text{mol})^{-1}

Step-by-step solution

The ideal gas equation is given by PV=nRTPV = nRT.

Rearranging for the gas constant RR, we get:

R=PVnTR = \dfrac{PV}{nT}

The dimensions of pressure PP (Force/Area) are [ML−1T−2][M L^{-1} T^{-2}].

The dimensions of volume VV are [L3][L^3].

The dimensions of number of moles nn are [mol][\text{mol}] and temperature TT are [K][K].

Substituting these dimensions into the equation for RR, we get:

[R]=[ML−1T−2][L3][mol][K][R] = \dfrac{[M L^{-1} T^{-2}][L^3]}{[\text{mol}][K]}

[R]=[ML2T−2K−1(mol)−1][R] = [M L^2 T^{-2} K^{-1} (\text{mol})^{-1}]
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