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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Introduction to Physics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Introduction to Physics

Assuming force, length, and time to be the fundamental quantities,...

Assuming force, length, and time to be the fundamental quantities, determine the dimensions of momentum.

Options

  1. AF2TF^2T
  2. BFT−1FT^{-1}
  3. CFTFT
  4. DFLT−1FLT^{-1}

Correct answer

C. FTFT

Step-by-step solution

The dimensional formula for momentum is [p]=MLT−1[p] = MLT^{-1}.

The dimensional formula for force is [F]=MLT−2[F] = MLT^{-2}.

We can express the dimensions of momentum as [p]=(MLT−2)×T[p] = (MLT^{-2}) \times T.

Substituting the fundamental quantity force FF and time TT, we get [p]=FT[p] = FT.
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