Two cars possessing unequal masses are equipped with similar tyres. If they travel at identical initial speeds, the minimum stopping distance

Step-by-step solution

Let the mass of the car be m and its initial speed be u . The maximum frictional force acting on the car when brakes are applied is f = N = m g , where is the coefficient of friction between the tyres and the road. The deceleration of the car is a = f m = m g m = g . Using the third equation of motion, v^2 = u^2 - 2as . For the minimum stopping distance s , the final velocity v = 0 . 0 = u^2 - 2( g)s s = u^2 2 g Since both cars have similar tyres, the coefficient of friction is the same. They also have identical in