Assume all the electrons in 100 g of water are lumped together to form a negatively charged particle, while all the nuclei are lumped together to form a positively charged particle. If these two particles are situated

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Correct answer: A. 2.56 × 10^ 25 N

Molar mass of water ( H_2O ) is 18 g/mol . Number of moles in 100 g of water = (100)/(18) . Taking Avogadro's number N_A = 6 × 10^ 23 mol^ -1 , the number of water molecules is: N = (100)/(18) × 6 × 10^ 23 = 10^ 25 3 Each water molecule contains 10 electrons and 10 protons. Total number of electrons = 10 × 10^ 25 3 = 10^ 26 3 . Total negative charge q_1 = - 10^ 26 3 × 1.6 × 10^ -19 = -(1.6 × 10^7)/(3) C . Total positive charge q_2 = +(1.6 × 10^7)/(3) C . Distance between the charges r = 10.0 cm = 0.1 m . Force of attraction F = (1)/(4π _0) (|q_1 q_2|)/(r^2) . F = 9 × 10^9 × (((1.6 × 10^7)/(3))^2)/((0.1)^2) F = 9 × 10^9 × 2.56 × 10^ 14 9 × 100 F = 2.56 × 10^ 25 N .

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