An NaCl molecule is bound by the electric force between the sodium and chlorine ions when one electron from sodium is transferred to chlorine. Assuming the ions act as point charges and taking the separation between

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Correct answer: A. 3.05 × 10^ -9 N

The charges on the sodium and chlorine ions are

+e

and

-e

respectively, where

e = 1.6 \times 10^{-19} \text{ C}

.

The separation between the ions is

r = 2.75 \times 10^{-8} \text{ cm} = 2.75 \times 10^{-10} \text{ m}

.

Using Coulomb's law, the force of attraction is given by:

F = \dfrac{1}{4\pi\epsilon_0} \dfrac{q_1 q_2}{r^2}

Substituting the values:

F = \dfrac{9 \times 10^9 \times (1.6 \times 10^{-19})^2}{(2.75 \times 10^{-10})^2}

F = \dfrac{9 \times 10^9 \times 2.56 \times 10^{-38}}{7.5625 \times 10^{-20}}

F = \dfrac{23.04 \times 10^{-29}}{7.5625 \times 10^{-20}}

F \approx 3.05 \times 10^{-9} \text{ N}

An NaCl molecule is bound by the electric force between the sodium...

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