A particle with a mass of 1 g and a charge of 2.5 10⁻⁴ C is released from rest within an electric field of 1.2 10^4 N C ⁻¹ . Determine the time it will take for the particle to cover a distance of 40 cm .

Step-by-step solution

The force experienced by the particle in the electric field is given by: F = qE Substituting the given values: F = (2.5 10⁻⁴ C ) (1.2 10^4 N C ⁻¹) = 3.0 N The acceleration of the particle is: a = F m = 3.0 N 10⁻³ kg = 3000 m s ⁻² Using the second equation of motion for a particle starting from rest ( u = 0 ): s = 1 2 at^2 Substituting s = 40 cm = 0.4 m : 0.4 = 1 2 3000 t^2 t^2 = 0.8 3000 = 8 3 10⁻⁴ s ^2 t = 8 3 10⁻² s 1.63 10⁻² s