A particle with a mass of 1 g and a charge of 2.5 × 10^ -4 C is released from rest within an electric field of 1.2 × 10^4 N C^ -1 . Determine the time it will take for the particle to cover a distance of 40 cm .

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Quantrex Academy · Accepted Answer

Correct answer: D. 1.63 × 10^ -2 s

The force experienced by the particle in the electric field is given by:

F = qE

Substituting the given values:

F = (2.5 \times 10^{-4} \text{ C}) \times (1.2 \times 10^4 \text{ N C}^{-1}) = 3.0 \text{ N}

The acceleration of the particle is:

a = \dfrac{F}{m} = \dfrac{3.0 \text{ N}}{10^{-3} \text{ kg}} = 3000 \text{ m s}^{-2}

Using the second equation of motion for a particle starting from rest (

u = 0

):

s = \dfrac{1}{2}at^2

Substituting

s = 40 \text{ cm} = 0.4 \text{ m}

:

0.4 = \dfrac{1}{2} \times 3000 \times t^2

t^2 = \dfrac{0.8}{3000} = \dfrac{8}{3} \times 10^{-4} \text{ s}^2

t = \sqrt{\dfrac{8}{3}} \times 10^{-2} \text{ s} \approx 1.63 \times 10^{-2} \text{ s}

A particle with a mass of 1 g and a charge of 2.5 × 10^ -4 C is...

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