Concepts Of Physics MCQ Edition [Volume 2]PhysicsElectric Field and Potential
A particle with a mass of 1 g and a charge of 2.5 10⁻⁴ C is released from rest within an electric field of 1.2 10^4 N C ⁻¹ . Determine the respective magnitudes of the electric force and the gravitational force acting on this particle.
Options
- A3.0 N , 9.8 10⁻⁴ N
- B0.3 N , 9.8 10⁻² N
- C3.0 10⁻² N , 9.8 10⁻³ N
- D3.0 N , 9.8 10⁻³ N
Correct answer
D. 3.0 N , 9.8 10⁻³ N
Step-by-step solution
Given, mass of the particle m = 1 g = 10⁻³ kg Charge of the particle q = 2.5 10⁻⁴ C Electric field E = 1.2 10^4 N C ⁻¹ The magnitude of the electric force is given by F_e = qE F_e = (2.5 10⁻⁴) (1.2 10^4) = 3.0 N The magnitude of the gravitational force is given by F_g = mg F_g = (10⁻³) 9.8 = 9.8 10⁻³ N