A particle with a mass of 1 g and a charge of 2.5 × 10^ -4 C is released from rest within an electric field of 1.2 × 10^4 N C^ -1 . Determine the respective magnitudes of the electric force and the gravitational force

Correct answer: D. 3.0 N , 9.8 × 10^ -3 N Given, mass of the particle m = 1 g = 10^ -3 kg Charge of the particle q = 2.5 × 10^ -4 C Electric field E = 1.2 × 10^4 N C^ -1 The magnitude of the electric force is given by F_e = qE F_e = (2.5 × 10^ -4 ) × (1.2 × 10^4) = 3.0 N The magnitude of the gravitational force is given by F_g = mg F_g = (10^ -3 ) × 9.8 = 9.8 × 10^ -3 N

Concepts Of Physics MCQ Edition [Volume 2]

Exam: Concepts Of Physics MCQ Edition [Volume 2]
Subject: Physics
Chapter: Electric Field and Potential

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Electric Field and Potential

A particle with a mass of 1 g and a charge of 2.5 × 10^ -4 C is...

A particle with a mass of

1 \text{ g}

and a charge of

2.5 \times 10^{-4} \text{ C}

is released from rest within an electric field of

1.2 \times 10^4 \text{ N C}^{-1}

. Determine the respective magnitudes of the electric force and the gravitational force acting on this particle.

Options

A $3.0 \text{ N}$ , $9.8 \times 10^{-4} \text{ N}$
B $0.3 \text{ N}$ , $9.8 \times 10^{-2} \text{ N}$
C $3.0 \times 10^{-2} \text{ N}$ , $9.8 \times 10^{-3} \text{ N}$
D $3.0 \text{ N}$ , $9.8 \times 10^{-3} \text{ N}$

Correct answer

D. $3.0 \text{ N}$ , $9.8 \times 10^{-3} \text{ N}$

Step-by-step solution

Given, mass of the particle

m = 1 \text{ g} = 10^{-3} \text{ kg}

Charge of the particle

q = 2.5 \times 10^{-4} \text{ C}

Electric field

E = 1.2 \times 10^4 \text{ N C}^{-1}

The magnitude of the electric force is given by

F_e = qE

F_e = (2.5 \times 10^{-4}) \times (1.2 \times 10^4) = 3.0 \text{ N}

The magnitude of the gravitational force is given by

F_g = mg

F_g = (10^{-3}) \times 9.8 = 9.8 \times 10^{-3} \text{ N}

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