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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Electric Field and Potential

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Electric Field and Potential

A ball having a mass of 100 g and a charge of 4.9 × 10^ -5 C is...

A ball having a mass of 100 g100 \text{ g} and a charge of 4.9×10−5 C4.9 \times 10^{-5} \text{ C} is released from rest into an area containing a horizontal electric field of 2.0×104 N C−12.0 \times 10^4 \text{ N C}^{-1}. Describe the path taken by the ball.

Options

  1. AA circular path
  2. BA parabolic trajectory opening horizontally
  3. CA straight line along the resultant force
  4. DA parabolic trajectory opening downwards

Correct answer

C. A straight line along the resultant force

Step-by-step solution

The forces acting on the ball are the gravitational force acting downwards and the electric force acting horizontally.

Gravitational force is Fg=mg=0.1×9.8=0.98 NF_g = mg = 0.1 \times 9.8 = 0.98 \text{ N}.

Electric force is Fe=qE=4.9×10−5×2.0×104=0.98 NF_e = qE = 4.9 \times 10^{-5} \times 2.0 \times 10^4 = 0.98 \text{ N}.

Both forces are constant in magnitude and direction, so their resultant force is also a constant vector.

Since the ball is released from rest, its initial velocity is zero. Under the action of a constant resultant force with zero initial velocity, the acceleration is constant and the particle moves in a straight line along the direction of the resultant force.
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