A uniform electric field of 10 N C ⁻¹ exists in the vertically downward direction. Determine the increase in the electric potential when moving upward through a height of 50 cm .

Step-by-step solution

The relationship between electric field and potential difference is given by V = - E r . Given that the electric field is in the vertically downward direction and the displacement is in the upward direction, the angle between E and r is 180^ . Magnitude of electric field, E = 10 N C ⁻¹ . Displacement, r = 50 cm = 0.5 m . Increase in electric potential, V = -E r (180^ ) = E r . Substituting the values, V = 10 0.5 = 5 V .