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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Electric Field and Potential

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Electric Field and Potential

A sample of HCl gas is placed within an electric field of 2.5 ×...

A sample of HCl gas is placed within an electric field of 2.5×104 N C−12.5 \times 10^4 \text{ N C}^{-1}. The dipole moment of each HCl molecule is 3.4×10−30 C m3.4 \times 10^{-30} \text{ C m}. Determine the maximum torque that can act on a molecule.

Options

  1. A4.25×10−26 N m4.25 \times 10^{-26} \text{ N m}
  2. B1.36×10−34 N m1.36 \times 10^{-34} \text{ N m}
  3. C8.5×10−26 N m8.5 \times 10^{-26} \text{ N m}
  4. D8.5×10−25 N m8.5 \times 10^{-25} \text{ N m}

Correct answer

C. 8.5×10−26 N m8.5 \times 10^{-26} \text{ N m}

Step-by-step solution

The torque acting on an electric dipole in a uniform electric field is given by τ=pEsin⁡θ\tau = pE \sin \theta, where pp is the dipole moment, EE is the electric field, and θ\theta is the angle between the dipole moment and the electric field.

The torque is maximum when θ=90∘\theta = 90^{{}^{{}^{\circ}}}, which gives sin⁡θ=1\sin \theta = 1.

\tau_{\text\max} = pE

Given:
p=3.4×10−30 C mp = 3.4 \times 10^{-30} \text{ C m}
E=2.5×104 N C−1E = 2.5 \times 10^4 \text{ N C}^{-1}

Substituting the values:
\tau_{\text\max} = (3.4 \times 10^{-30}) \times (2.5 \times 10^4)

\tau_{\text\max} = 8.5 \times 10^{-26} \text{ N m}
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