Two particles A and B , possessing opposite charges of +2.0 10⁻⁶ C and -2.0 10⁻⁶ C , are positioned at a separation of 1.0 cm . Determine the electric dipole moment of this pair.

Step-by-step solution

The magnitude of each charge is q = 2.0 10⁻⁶ C . The separation distance between the charges is d = 1.0 cm = 1.0 10⁻² m . The electric dipole moment p is given by the product of the magnitude of either charge and the separation distance between them: p = q d p = (2.0 10⁻⁶) (1.0 10⁻²) p = 2.0 10⁻⁸ C m