Two particles A and B , possessing opposite charges of +2.0 × 10^ -6 C and -2.0 × 10^ -6 C , are positioned at a separation of 1.0 cm . Determine the electric dipole moment of this pair.

Correct answer: C. 2.0 × 10^ -8 C m The magnitude of each charge is q = 2.0 × 10^ -6 C . The separation distance between the charges is d = 1.0 cm = 1.0 × 10^ -2 m . The electric dipole moment p is given by the product of the magnitude of either charge and the separation distance between them: p = q × d p = (2.0 × 10^ -6 ) × (1.0 × 10^ -2 ) p = 2.0 × 10^ -8 C m

Concepts Of Physics MCQ Edition [Volume 2]

Exam: Concepts Of Physics MCQ Edition [Volume 2]
Subject: Physics
Chapter: Electric Field and Potential

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Electric Field and Potential

Two particles A and B , possessing opposite charges of +2.0 × 10^...

Two particles

A

and

B

, possessing opposite charges of

+2.0 \times 10^{-6} \text{ C}

and

-2.0 \times 10^{-6} \text{ C}

, are positioned at a separation of

1.0 \text{ cm}

. Determine the electric dipole moment of this pair.

Options

A $4.0 \times 10^{-8} \text{ C m}$
B $1.0 \times 10^{-8} \text{ C m}$
C $2.0 \times 10^{-8} \text{ C m}$
D $2.0 \times 10^{-6} \text{ C m}$

Correct answer

C. $2.0 \times 10^{-8} \text{ C m}$

Step-by-step solution

The magnitude of each charge is

q = 2.0 \times 10^{-6} \text{ C}

.

The separation distance between the charges is

d = 1.0 \text{ cm} = 1.0 \times 10^{-2} \text{ m}

.

The electric dipole moment

p

is given by the product of the magnitude of either charge and the separation distance between them:

p = q \times d

p = (2.0 \times 10^{-6}) \times (1.0 \times 10^{-2})

p = 2.0 \times 10^{-8} \text{ C m}

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