Two particles A and B , possessing opposite charges of +2.0 10⁻⁶ C and -2.0 10⁻⁶ C , are positioned at a separation of 1.0 cm . Determine the electric field at a point located on the axis of the dipole, 1.0 m away from the centre.

Step-by-step solution

The dipole moment p is given by p = q 2a Substituting the given values: p = 2.0 10⁻⁶ 1.0 10⁻² = 2.0 10⁻⁸ C m The electric field on the axis of a short dipole ( r a ) is given by: E = 1 4 ₀ 2p r^3 Substituting the known values ( r = 1.0 m and 1 4 ₀ = 9 10^9 N m ^2 C ⁻² ): E = 9 10^9 2 2.0 10⁻⁸ (1.0)^3 E = 36 10 = 360 N C ⁻¹