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JEE Main20245 Apr 2024Morning ShiftChemistryp Block Elements (Group 13 & 14)Actual

The number of neutrons present in the more abundant isotope of boron is ' (x ) '. Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is ' (y ) '. The value of (x+y ) is _______

Options

  1. A3
  2. B9
  3. C4
  4. D6

Correct answer

B. 9

Step-by-step solution

More abundant isotope = B ¹¹ [Number of neutrons =6 ] aligned & x =6 & ~B + O ₂ B ₂ O ₃ aligned Oxidation state of B in B ₂ O ₃=+3 So, y=3 Hence x+y=9

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