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JEE Main 20245 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
5 April
Shift
Morning Shift
Subject
Chemistry
Chapter
p Block Elements (Group 13 & 14)

JEE Main 2024 · 5 April · Morning Shift · Chemistry · p Block Elements (Group 13 & 14)

The number of neutrons present in the more abundant isotope of...

The number of neutrons present in the more abundant isotope of boron is ' xx '. Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is ' yy '. The value of x+yx+y is _______

Options

  1. A3
  2. B9
  3. C4
  4. D6

Correct answer

B. 9

Step-by-step solution

More abundant isotope =B11=\mathrm{B}^{11} [Number of neutrons =6=6 ] x=6 B+O2→B2O3\begin{aligned} & \mathrm{x}=6 \\ & \mathrm{~B}+\mathrm{O}_2 \rightarrow \mathrm{B}_2 \mathrm{O}_3 \end{aligned} Oxidation state of BinB2O3=+3\mathrm{B} in \mathrm{B}_2 \mathrm{O}_3=+3 So, y=3y=3 Hence x+y=9x+y=9
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