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JEE Main202225 Jul 2022Morning ShiftChemistryp Block Elements (Group 13 & 14)Actual

The geometry around boron in the product ' B ' formed from the following reaction is BF 3 + NaH ⟶ 450 K A + NaF A + NMe 3 → B

Options

  1. Atrigonal planar
  2. Btetrahedral
  3. Cpyramidal
  4. Dsquare planar

Correct answer

B. tetrahedral

Step-by-step solution

2 BF 3 + 6 NaH → B 2 H 6 A + 6 NaF In this reaction hydride ions replace the fluoride ions. and diborane is formed, which is a Lewis acid due to incomplete octet. It breaks symmetrically with bases like tertiary amines. B 2 H 6 + 2 Me 3 N → 2 Me 3 N + B BH 3 - In this product geometry around Boron will be tetrahedral. And it will have sp 3 hybridisation.

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