JEE Main 202124 FebruaryMorning Shift

JEE Main 2021 · 24 February · Morning Shift · Chemistry · p Block Elements (Group 13 & 14)

Al _ 2 O _ 3 was leached with alkali to get X . The solution of X...

${Al}_{2}{O}_{3}$ was leached with alkali to get $X .$ The solution of $X$ on passing of gas $Y,$ forms $Z .$

$X, Y$ and $Z$ respectively are

Options

A $X = Al{\left(OH\right)}_{3}, Y = CO{2}^{'}, Z = {Al}_{2}{O}_{3}$
B $X = Na\left[Al{\left(OH\right)}_{4}\right], Y = {SO}_{2}, Z = {Al}_{2}{O}_{3}$
C $X = Al{\left(OH\right)}_{3}, Y = {SO}_{2}, Z = {Al}_{2}{O}_{3} \cdot {xH}_{2}O$
D $X = Na\left[Al{\left(OH\right)}_{4}\right], Y = {CO}_{2}, Z = {Al}_{2}{O}_{3}, x{H}_{2}O$

D. $X = Na\left[Al{\left(OH\right)}_{4}\right], Y = {CO}_{2}, Z = {Al}_{2}{O}_{3}, x{H}_{2}O$

Al _ 2 O _ 3 was leached with alkali to get X . The solution of X on passing of gas Y, forms Z . X, Y and Z

(1) ${Al}_{2}{O}_{3} + NaOH ⟶ \mathop{Na\left[Al ( OH{)}_{4}\right]}_{" X "}$

(2) $Na\left[Al ( OH{)}_{4}\right]\mathop{\to}_{" Y "}^{{CO}_{2}}\mathop{Al ( OH{)}_{3}}_{" Z "}$ or ${Al}_{2}{O}_{3} \cdot {xH}_{2}O$

So, when ${Al}_{2}{O}_{3}$ was leached with alkali to get $X .$ The solution of $X$ on passing of gas $Y,$ forms $Z .$

$X, Y$ and $Z$ respectively are

$X: Na\left[Al{\left(OH\right)}_{4}\right]$

$Y: {CO}_{2}$

$Z: {Al}_{2}{O}_{3} \cdot {xH}_{2}O$