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JEE Main202124 Feb 2021Morning ShiftChemistryp Block Elements (Group 13 & 14)Actual

Al 2 O 3 was leached with alkali to get X . The solution of X on passing of gas Y , forms Z . X , Y and Z respectively are

Options

  1. AX = Al OH 3 , Y = CO 2 ' ,   Z = Al 2 O 3
  2. BX = Na Al OH 4 , Y = SO 2 ,   Z = Al 2 O 3
  3. CX = Al OH 3 ,   Y = SO 2 ,   Z = Al 2 O 3 · xH 2 O
  4. DX = Na Al OH 4 ,   Y = CO 2 ,   Z = Al 2 O 3 ,   x H 2 O

Correct answer

D. X = Na Al OH 4 ,   Y = CO 2 ,   Z = Al 2 O 3 ,   x H 2 O

Step-by-step solution

(1) Al 2 O 3 + NaOH ⟶ Na Al ( OH ) 4 " X " (2) Na Al ( OH ) 4 → " Y " CO 2 Al ( OH ) 3 " Z " or Al 2 O 3 · xH 2 O So, when Al 2 O 3 was leached with alkali to get X . The solution of X on passing of gas Y , forms Z . X , Y and Z respectively are X : Na Al OH 4 Y : CO 2 Z : Al 2 O 3 · xH 2 O

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