Calculate the number of oxygen atoms required to combine with 7 g of N 2 to form N 2 O 3 when 80 % of N 2 is converted to N 2 O 3 .

Step-by-step solution

for formation of N 2 O 3 2 N 2 + 3 O 2 → 2 N 2 O 3 2 moles of N 2 combines with 3 m o l e of O 2 Given, 7 g m N 2 ( 80 % only reacts ) i . e . 5.6 g m o f N 2 Mole of N 2 = 5.6 28 = 0.2 Hence 2 0.2 = 3 x m o l e o f O 2 x = 0.3 moles Number of atoms = 0.3 × 2 × 6.023 × 1 0 23 = 3.61 × 1 0 23