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Highly selective Backlog Qs for JEE MainChemistrySome Basic Concepts of Chemistry

40% (w/v) of NaCl solution (specific gravity = 1.12) is equivalent to

Options

  1. A3.57 × 1 0 5 ppm
  2. B3.57 × 1 0 6 ppm
  3. C1 × 1 0 6 ppm
  4. D4 × 1 0 5 ppm

Correct answer

A. 3.57 × 1 0 5 ppm

Step-by-step solution

Volume of solution = 100 mL Mass of solution = Volume × density Mass of solution = 100 × 1.12 = 112 g Concentration in ppm = W s o l u t e W s o l u t i o n × 1 0 6 ppm in NaCl solution = 40 112 × 1 0 6 = 3.57 × 1 0 5 ppm.

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