Sulphur trioxide is prepared by the following two reactions: S 8 ( s ) + 8 O 2 ( g ) → 8 SO 2 ( g ) 2 SO 2 ( g ) + O 2 ( g ) → 2 SO 3 ( g ) How many grams of SO 3 are produced from 1   mol of S 8 ?

Step-by-step solution

From the first reaction: 1   mol   of   S 8   →   8   mol   of   SO 2 Hence, SO 2 after the first reaction will be 8 moles. Now, from the second reaction: 2   mol   of   SO 2   →   2   mol   of   SO 3 ∴   8   mol   of   SO 2   →   8   mol   of   SO 3 Therefore, the mass of sulphur trioxide produced = Number   of   moles × Molecular   weight = 8 &#21