Highly selective Backlog Qs for JEE MainMathematicsEllipse
An ellipse is drawn by taking a diameter of the circle (x-1)^2+y^2=1 as its semiminor axis and a diameter of the circle x^2+(y-2)^2=4 as its semi-major axis. If the centre of the ellipse is the origin and its axes are the coordinate axes, then the equation of the ellipse is
Options
- A4 x^2+y^2=4
- Bx^2+4 y^2=8
- C4 x^2+y^2=8
- Dx^2+4 y^2=16
Correct answer
D. x^2+4 y^2=16
Step-by-step solution
Semi minor axis b=2 Semi major axis a=4 Equation of ellipse = x^2 a^2 + y^2 b^2 =1 x^2 16 + y^2 4 =1 x^2+4 y^2=16 .