JEE Main 202311 AprilEvening Shift

Exam: JEE Main
Year: 2023
Date: 11 April
Shift: Evening Shift
Subject: Chemistry
Chapter: p Block Elements (Group 15, 16, 17 & 18)

JEE Main 2023 · 11 April · Evening Shift · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

One mole of P _ 4 reacts with 8 moles of SOCl _ 2 to give 4 moles...

One mole of

{P}_{4}

reacts with

8

moles of

{SOCl}_{2}

to give

4

moles of

A

x

mole of

{SO}_{2}

and

2

moles of

B

A, B

and

x

respectively are

Options

A ${POCl}_{3}, {S}_{2}{Cl}_{2}$ and $2$
B ${PCl}_{3}, {S}_{2}{Cl}_{2}$ and $4$
C ${PCl}_{3}, {S}_{2}{Cl}_{2}$ and $2$
D ${POCl}_{3}, {S}_{2}{Cl}_{2}$ and $4$

Correct answer

B. ${PCl}_{3}, {S}_{2}{Cl}_{2}$ and $4$

Step-by-step solution

Thionyl chloride reacts with white phosphorus to produce phosphorus trichloride. The other side products in this reaction are sulphur dioxide and Sulphur monochloride.

${P}_{4} + 8{SOCl}_{2} \to 4{PCl}_{3} + 4{SO}_{2} + 2{S}_{2}{Cl}_{2}$
Hence $A = {PCl}_{3}, x = 4, B = {S}_{2}{Cl}_{2}$

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