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JEE Main
Exam
JEE Main
Subject
Mathematics
Chapter
Trigonometric Ratios & Identities

JEE Main · Mathematics · Trigonometric Ratios & Identities

If θ+ (θ+(π)/(3))+ (θ+(2 π)/(3))=3 , then which of the following is...

If tan⁡θ+tan⁡(θ+π3)+tan⁡(θ+2π3)=3\tan \theta+\tan \left(\theta+\frac{\pi}{3}\right)+\tan \left(\theta+\frac{2 \pi}{3}\right)=3, then which of the following is equal to 1 ?

Options

  1. Atan⁡2θ\tan 2 \theta
  2. Btan⁡3θ\tan 3 \theta
  3. Ctan⁡2θ\tan ^2 \theta
  4. Dtan⁡3θ\tan ^3 \theta

Correct answer

B. tan⁡3θ\tan 3 \theta

Step-by-step solution

Given, tan⁡θ+tan⁡(θ+π3)+tan⁡(θ+2π3)=3⇒tan⁡θ+tan⁡θ+31−3tan⁡θ+tan⁡θ−31+3tan⁡θ=3⇒tan⁡θ+8tan⁡θ1−3tan⁡2θ=3⇒9tan⁡θ−3tan⁡3θ1−3tan⁡2θ=3⇒3tan⁡3θ=3⇒tan⁡3θ=1\begin{aligned}& \tan \theta+\tan \left(\theta+\frac{\pi}{3}\right)+\tan \left(\theta+\frac{2 \pi}{3}\right)=3 \\ & \Rightarrow \tan \theta+\frac{\tan \theta+\sqrt{3}}{1-\sqrt{3} \tan \theta}+\frac{\tan \theta-\sqrt{3}}{1+\sqrt{3} \tan \theta}=3 \\ & \Rightarrow \quad \tan \theta+\frac{8 \tan \theta}{1-3 \tan ^2 \theta}=3 \\ & \Rightarrow \quad \frac{9 \tan \theta-3 \tan ^3 \theta}{1-3 \tan ^2 \theta}=3 \\ & \Rightarrow \quad 3 \tan 3 \theta=3 \Rightarrow \tan 3 \theta=1 \\ & \end{aligned}Hence, option (2) is correct.
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