Highly selective Backlog Qs for JEE MainMathematicsTrigonometric Ratios & Identities
The value of cos 2 π 7 + cos 4 π 7 + cos 6 π 7 is equal to
Options
- A- 1
- B- 1 2
- C- 1 3
- D- 1 4
Correct answer
B. - 1 2
Step-by-step solution
Given, cos 2 π 7 + cos 4 π 7 + cos 6 π 7 = 1 2 sin π 7 2 cos 2 π 7 sin π 7 + 2 cos 4 π 7 sin π 7 + 2 cos 6 π 7 sin π 7 = 1 2 sin π 7 sin 3 π 7 - sin π 7 + sin 5 π 7 - sin 3 π 7 + sin 7 π 7 - sin 5 π 7 Since, 2 cos A sin B = sin A + B - sin A - B = 1 2 sin π 7 - sin π 7 + sinπ = - 1 2 , ∵ sinπ = 0