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JEE Main20236 Apr 2023Morning ShiftChemistryp Block Elements (Group 15, 16, 17 & 18)Actual

Match List-I with . List-I Name of reaction List-II Reagent used A Hell-Volhard Zelinsky reaction I NaOH + I 2 B Iodoform reaction II ( i ) CrO 2 Cl 2 , CS 2 ( ii ) H 2 O C Etard reaction III ( i ) Br 2 / red phosphorus ( ii ) H 2 O D Gatterman-Koch reaction IV CO , HCl , anhyd . AlCl 3 Choose the correct answer from the options given below:

Options

  1. AA → III ; B → I ; C → II ; D → IV
  2. BA → I ; B → II ; C → III ; D → IV
  3. CA → III ; B → II ; C → I ; D → IV
  4. DA → III ; B → I ; C → IV ; D → II

Correct answer

A. A → III ; B → I ; C → II ; D → IV

Step-by-step solution

(A) Hell-Volhard-Zelinsky reaction: Carboxylic acid react with chlorine or bromine in the presence of phosphorus to give α - halogenated carboxylic acids. The halogenation continues till all the hydrogen atom in the α - position are replaced by halogen atoms. This reaction is called HVZ (Hell-Volhard-Zelinsky) reaction. CH 3 COOH   Acetic   acid → - HCl Cl 2 ,   P 4   ClCH 2 COOH Chloroacetic   acid → - HCl Cl 2 ,   P 4 Cl 2 CHCOOH Dichloroacetic   acid &#859

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