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JEE Main 20236 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
6 April
Shift
Morning Shift
Subject
Chemistry
Chapter
p Block Elements (Group 15, 16, 17 & 18)

JEE Main 2023 · 6 April · Morning Shift · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

Match List-I with . List-I Name of reaction List-II Reagent used A...

Match List-I with .

List-I

Name of reaction

List-II

Reagent used

AA Hell-Volhard Zelinsky reaction II NaOH+I2NaOH + {I}_{2}
BB Iodoform reaction IIII (i)CrO2Cl2,CS2(ii)H2O( i ) {CrO}_{2}{Cl}_{2}, {CS}_{2} ( ii ) {H}_{2}O
CC Etard reaction IIIIII (i)Br2/redphosphorus(ii)H2O( i ) {Br}_{2} / redphosphorus ( ii ) {H}_{2}O
DD Gatterman-Koch reaction IVIV CO,HCl,anhyd.AlCl3CO, HCl, anhyd . {AlCl}_{3}

Choose the correct answer from the options given below:

Options

  1. AA→III;B→I;C→II;D→IVA \to III; B \to I; C \to II; D \to IV
  2. BA→I;B→II;C→III;D→IVA \to I; B \to II; C \to III; D \to IV
  3. CA→III;B→II;C→I;D→IVA \to III; B \to II; C \to I; D \to IV
  4. DA→III;B→I;C→IV;D→IIA \to III; B \to I; C \to IV; D \to II

Correct answer

A. A→III;B→I;C→II;D→IVA \to III; B \to I; C \to II; D \to IV

Step-by-step solution

(A) Hell-Volhard-Zelinsky reaction:

Carboxylic acid react with chlorine or bromine in the presence of phosphorus to give α−\alpha -halogenated carboxylic acids. The halogenation continues till all the hydrogen atom in the α−\alpha -position are replaced by halogen atoms. This reaction is called HVZ (Hell-Volhard-Zelinsky) reaction.

CH3COOHAceticacid→−HClCl2,P4ClCH2COOHChloroaceticacid→−HClCl2,P4Cl2CHCOOHDichloroaceticacid→−HClCl2,P4Cl3CCOOHTrichloroaceticacid\mathop{{CH}_{3}COOH}_{Aceticacid}\mathop{\to}_{- HCl}^{{Cl}_{2}, {P}_{4}}\mathop{{ClCH}_{2}COOH}_{Chloroaceticacid}\mathop{\to}_{- HCl}^{{Cl}_{2}, {P}_{4}}\mathop{{Cl}_{2}CHCOOH}_{Dichloroaceticacid}\mathop{\to}_{- HCl}^{{Cl}_{2}, {P}_{4}}\mathop{{Cl}_{3}CCOOH}_{Trichloroaceticacid}

(B) Iodoform reaction:

The Iodoform reaction is a chemical reaction where a iodoform(CHI3)\left({CHI}_{3}\right) is produced by the full iodonation of a methyl ketone (RCOCH3{RCOCH}_{3}, where RR can be either a hydrogen atom, an alkyl or an aryl group) in the presence of a base.

2NaOH+I2→NaOI+NaICH3COCH3+3NaOI→CH3COONa+CHI3+2NaOH2NaOH + {I}_{2} \to NaOI + NaI{CH}_{3}{COCH}_{3} + 3NaOI \to {CH}_{3}COONa + {CHI}_{3} + 2NaOH

(C) Etard reaction:

In Etard reaction, chromyl chloride oxidises methyl group to a chromium complex, which on hydrolysis gives corresponding Benzaldehyde. The equation for the reaction is:

C6H5−CH3+CrO2Cl2→CS2C6H5−CH(OCrOHCl2)→H3O+C6H5−CHO{C}_{6}{H}_{5} - {CH}_{3} + {CrO}_{2}{Cl}_{2}\overset{{CS}_{2}}{\to}{C}_{6}{H}_{5} - CH\left({OCrOHCl}_{2}\right)\overset{{H}_{3}{O}^{+}}{\to}{C}_{6}{H}_{5} - CHO

(D) Gatterman-Koch reaction

When benzene or its derivative is treated with carbon monoxide and hydrogen chloride in the presence of anhydrous aluminium chloride or cuprous chloride, it gives Benzaldehyde or substituted Benzaldehyde. The equation for the reaction is:

C6H5−CH3→Anh.AlCl3/CuClCO+HClC6H5−CHO{C}_{6}{H}_{5} - {CH}_{3}\mathop{\to}_{Anh . {AlCl}_{3} / CuCl}^{CO + HCl}{C}_{6}{H}_{5} - CHO

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