Match List I with List II List I Oxide List II Type of bond A N _ 2 O _ 4 I 1N = Obond B NO _ 2 II 1N – O – Nbond C N _ 2 O _ 5 III 1N – Nbond D N _ 2 O IV 1N = N / N ≡ Nbond Choose the correct answer from the options

Question

Quantrex Academy · Accepted Answer

Correct answer: A. A - III, B - I, C - II, D - IV

The coplanarity of N _ 2 O _ 4 results from a delicate balance of the repulsive forces, which favour the skew structure, and of the effects of bonding which favour the planar structure. NO _ 2 is a bent molecule. The N _ 2 O _ 5 molecule is a trigonal planar molecule. N _ 2 O has a linear, unsymmetrical structure that may be thought of as a hybrid of two resonance forms.

List I Oxide		List II Type of bond
$A$	${N}_{2}{O}_{4}$	$I$	$1N = Obond$
$B$	${NO}_{2}$	$II$	$1N – O – Nbond$
$C$	${N}_{2}{O}_{5}$	$III$	$1N – Nbond$
$D$	${N}_{2}O$	$IV$	$1N = N / N ≡ Nbond$

Match List I with List II List I Oxide List II Type of bond A N _ 2...

Options

Correct answer

Step-by-step solution

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