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Most Important Selected Qs for JEE AdvancedChemistryd and f Block Elements

Which of the following is/are correct?

Options

  1. AOn strong heating FeCl ₃ gives FeCl ₂ and Cl ₂
  2. BDilute CuCl ₂ is blue due to formation of [ CuCl ₄ ]²⁻
  3. CPH ₃ can be obtained by heating red P with NaOH
  4. DPH ₃, H ₃ PO ₃ and H ₃ PO ₂ , all are reducing agents

Correct answer

D. PH ₃, H ₃ PO ₃ and H ₃ PO ₂ , all are reducing agents

Step-by-step solution

FeCl ₃ FeCl ₂+ Cl ₂ Dilute CuCl ₂ is blue due to [ Cu ( H ₂ O )₄ ]²⁺ . PH ₃ is obtained be heating white P with NaOH . All are reducing because of weak P - H bond.

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