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JEE Advanced
Exam
JEE Advanced
Subject
Chemistry
Chapter
Practical Chemistry

JEE Advanced · Chemistry · Practical Chemistry

Select pair(s) in which both produces same coloured ppt. with...

Select pair(s) in which both produces same coloured ppt. with CrO42−\mathrm{CrO}_4^{2-} ion

Options

  1. ABa2+,Sr2+\mathrm{Ba}^{2+}, \mathrm{Sr}^{2+}
  2. BPb2+,Ba2+\mathrm{Pb}^{2+}, \mathrm{Ba}^{2+}
  3. CAg+,Ba2+\mathrm{Ag}^{+}, \mathrm{Ba}^{2+}
  4. DAg+,Hg22+\mathrm{Ag}^{+}, \mathrm{Hg}_2^{2+}

Correct answer

D. Ag+,Hg22+\mathrm{Ag}^{+}, \mathrm{Hg}_2^{2+}

Step-by-step solution

\left.Ba2+→CrO42−BaCrO4 Pb2+→CrO42−PbCrO4Sr2+→CrO42−SrCrO4\begin{array}{l}\mathrm{Ba}^{2+} \xrightarrow{\mathrm{CrO}_4^{2-}} \mathrm{BaCrO}_4 \\ \mathrm{~Pb}^{2+} \xrightarrow{\mathrm{CrO}_4^{2-}} \mathrm{PbCrO}_4 \\ \mathrm{Sr}^{2+} \xrightarrow{\mathrm{CrO}_4^{2-}} \mathrm{SrCrO}_4\end{array}\right\}Yellow ppt. \left.2Ag+→CrO42Ag2CrO4Hg22+→CrO42−Hg2CrO4\begin{array}{l}2 \mathrm{Ag}^{+} \xrightarrow{\mathrm{CrO}_4^2} \mathrm{Ag}_2 \mathrm{CrO}_4 \\ \mathrm{Hg}_2^{2+} \xrightarrow{\mathrm{CrO}_4^{2-}} \mathrm{Hg}_2 \mathrm{CrO}_4\end{array}\right\} Red ppt.
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