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Most Important Selected Qs for JEE AdvancedChemistrySome Basic Concepts of Chemistry

When 1 gram of oleum is diluted with water to make 100 mL solution. 100 mL of solution needs 100 mL of 0.24 M NaOH for complete neutralization. Select the correct statement(s) (Density of all solutions is 1 ~g / cc )

Options

  1. ALabel of given oleum is 117.6 %
  2. B% of free SO ₃ is 78.2
  3. CMolarity of H ₂ SO ₄ solution after dilution is 0.12 M
  4. D% of free SO ₃ is 21.8

Correct answer

C. Molarity of H ₂ SO ₄ solution after dilution is 0.12 M

Step-by-step solution

aligned & 100 M 2 =100 0.24 & M _ H ₂ SO ₄ =0.12 M & 2 n _ H ₂ SO ₄ =100 0.24 10⁻³ & n _ H ₂ SO ₄ =0.012 w_ H ₂ SO ₄ =1.176 gm aligned So 1 gm oleum gives 1.176 gm H ₂ SO ₄ by consuming 0 . 1 7 6 g m of H ₂ O % free SO ₃ in oleum = 78.2 %

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